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Pushout - What does it mean?

pushout | |

is likely misspelled.


has no English definition.

As a noun pushout

is given a pair of morphisms f:Z\rightarrow X and g: Z\rightarrow Y with a common domain, Z, their pushout is a pair of morphisms i_1:X\rightarrow P and i_2:Y\rightarrow P as well as their common codomain, P, such that the equation i_1 \circ f = i_2 \circ g is satisfied, and for which there is the universal property that for any other object Q for which there are also morphisms j_1: X\rightarrow Q and j_2: Y\rightarrow Q; there is a unique morphism u: P\rightarrow Q such that u \circ i_1 = j_1 and u \circ i_2 = j_2.

pushout

English

Noun

(en noun)
  • (category theory) Given a pair of morphisms f:Z\rightarrow X and g: Z\rightarrow Y with a common domain, Z'', their pushout is a pair of morphisms i_1:X\rightarrow P and i_2:Y\rightarrow P as well as their common codomain, ''P'', such that the equation i_1 \circ f = i_2 \circ g is satisfied, and for which there is the ''universal property'' that for any other object ''Q for which there are also morphisms j_1: X\rightarrow Q and j_2: Y\rightarrow Q; there is a unique morphism u: P\rightarrow Q such that u \circ i_1 = j_1 and u \circ i_2 = j_2.
  • Antonyms

    * pullback

    Not English

    has no English definition. It may be misspelled.